I understand the common games tie breaker between division teams but what if Team A has played Team C twice (one loss, one win) and Team B has played Team C only once and won? Would Team A's pct = .500 while Team B's pct = 1.000 ? Do I count both games for Team A or only one (and if so, which one?) Thanks!

1 Answer 1


You don't specify which sport or league you're interested in, but I'm assuming it's the NFL since I know that's a criterion used there. If that's the case then by the NFL's tiebreaking procedure, they use the "best won-lost-tied percentage in common games." For your example, Team B would then win the tie-breaker. I think this makes perfect sense, too, and would expect to see the same method used for any other league that uses this criterion.

  • I have another question: What if two teams win their division with the same record, how do they determine who is seeded higher? i.e. Team A wins their division with a 13-3 record, Team B also wins their division with a 13-3 record. How do you determine who is seeded higher in the playoffs? Jan 1, 2016 at 4:12
  • From the link in my answer, the first tie-breaker is the head-to-head record against one another. If, for instance, they have each won and lost one game apiece versus each other, the next tie-breaker is the highest winning percentage against other teams within that division. Jan 2, 2016 at 3:00

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