3

I understand the common games tie breaker between division teams but what if Team A has played Team C twice (one loss, one win) and Team B has played Team C only once and won? Would Team A's pct = .500 while Team B's pct = 1.000 ? Do I count both games for Team A or only one (and if so, which one?) Thanks!

2

You don't specify which sport or league you're interested in, but I'm assuming it's the NFL since I know that's a criterion used there. If that's the case then by the NFL's tiebreaking procedure, they use the "best won-lost-tied percentage in common games." For your example, Team B would then win the tie-breaker. I think this makes perfect sense, too, and would expect to see the same method used for any other league that uses this criterion.

  • I have another question: What if two teams win their division with the same record, how do they determine who is seeded higher? i.e. Team A wins their division with a 13-3 record, Team B also wins their division with a 13-3 record. How do you determine who is seeded higher in the playoffs? – George Hicks Jan 1 '16 at 4:12
  • From the link in my answer, the first tie-breaker is the head-to-head record against one another. If, for instance, they have each won and lost one game apiece versus each other, the next tie-breaker is the highest winning percentage against other teams within that division. – Dr.DrfbagIII Jan 2 '16 at 3:00

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.