2

I'm a USBC League Bowler, and I'm tracking my own stats, and I want to know my Strike Rate Percentage.

Theoretically, you would take and divide the number of frames bowled by the number of strikes bowled, but how do you account for the tenth frame? If I bowl a perfect game, that's 100%. But let's take this scenario where I bowled a 232.

enter image description here

As you can see here I have 8 strikes in the game and 2 of them in the tenth frame. 8 strikes / 10 frames is 80% strike rate, but not when 2 of the strikes are in the tenth frame. 8 strikes / 12 first throw chances for 75%.

How do I figure this out in Excel?

Improve this question
1

Your divisor here isn't "frames", but the number of times you threw at a full rack. So with three full racks in the tenth with your sample game, you're correct that you should divide by 12.

If you don't close out the tenth, then you could be dividing by only 10.

Pseudocode for Excel. I'll indicate the ball number after the frame:

if (10.1 == "x" and 10.2 == "x") -> number of racks = 12
elseif (10.1 == "x" or 10.2 == "/") -> number of racks = 11
else -> number of racks = 10
Improve this answer
  • I admit it's unlikely to happen for anyone throwing strikes on a regular basis, but what happens if you miss entirely with the first ball of a frame - does that count as one or two attempts on a full rack? – Philip Kendall♦ Sep 16 '19 at 8:55
  • 1
    Unfortunately, while I found many sites discussing the concept, I did not find any "official" formula from a sanctioning body like USBC or PBA. So I can't say for sure. From a training point of view, it would make sense to count it as a strike attempt. But from a scoring point of view, it won't be a strike, so it's not one. Personally, I'd count it as only one attempt because the math is easier. Be great if someone can find a description of how official records are calculated. – BowlOfRed Sep 16 '19 at 9:02

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.