When watching a match of snooker, especially one where safety battles take place, the broadcaster will often display a "Safety Success" statistic for both players above the current score, or via a "summary" infographic. For example:

enter image description here

I imagine that, similar to Pot Success and Long Pot Success, Safety Success will use the total amount of the safety shots attempted by the player, and use this to divide against the number of successful attempts - but what makes a safety shot "successful" in this context?

  • Snookering the opponent?
  • Getting the ball within X distance of the baulk cushion?
  • Not leaving a on ball potable?
  • A combination of these?
  • If I were designing that stat, I would define it as "shots where the opponent fails to pot a ball on their next shot" as that is both easy to measure and captures the really important feature of a safety shot - not letting the opponent make a break. I have no idea if that's how it's defined in your example though.
    – Philip Kendall
    Sep 24, 2020 at 18:12
  • Just to make sure - are those rates possibly rates of safety shots that don't end in a foul (i.e., they correctly follow the rules for a safety shot)? Or is that much less common to occur than those rates would suggest?
    – Joe
    Sep 24, 2020 at 18:53

2 Answers 2


This is what I could find in a tweet from Snooker champion Neil Robertson:

Unfortunately it’s not. Someone in the van does it and the criteria is if you get the white past the baulk line from a safety. A successful long pot is of any ball travels 5 feet I think



One possible answer comes from the world of AI pool.

From the paper PickPocket: A computer billiards shark, we have the following basic definition:

A successful safety is one where the opponent fails to pocket an object ball on their next shot, thus the player gets to shoot again.

This is from billiards, not snooker specifically, but it's as good a definition as any, and the concept applies to both in any event.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.