Hit a no ball and run 4 runs. Then the fielder will throw that ball and it will go for a six..total 11 runs.

Is that possible?

  • Even though I agreed for close vote, I am wondering how would it be a duplicate since other questions are about scoring in one over and this one is about scoring in one ball. This is just a related question and not a duplicate one.
    – iDev
    Commented Aug 1, 2013 at 17:24
  • @ACB you should've considered that before closing the question. I find closing questions a serious matter.
    – Jacob Jan
    Commented Aug 1, 2013 at 19:11
  • I think that is why there is a reopen option. Unlike a downvote, you can always reopen a question which is closed. When I casted close vote, there was already a few comments on that and felt genuine. But when we read it on title, you can see that it is different. People should be more careful with downvotes which cant be reversed. Even if it is a duplicate doesn't mean that you have to downvote. It should be based on the quality of question.
    – iDev
    Commented Aug 1, 2013 at 21:33
  • 1
    @ACB this question had severe grammar problems. You could've closed it as "it's unclear what's being asked here", but you decided to go with the flow. Please pay more attention when closing questions.
    – Jacob Jan
    Commented Aug 3, 2013 at 9:38
  • Grammar problems don't mean that you need to close it. You can always edit the question and correct it. And closing is done by 5 people, not just one. People need to be careful with where they are using their down votes though. That is the major problem here.
    – iDev
    Commented Aug 3, 2013 at 11:56

1 Answer 1


Theoretically it is possible to score as many runs as possible since none of the cricket laws are putting a limit on that. So the answer is infinity.

And yes, what you have mentioned is possible. But if a fielder throws the ball after picking from the ground it won't be a six, but a four. So it will be 9 runs.


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